2.4 Find Multiples and Factors
The topics covered in this section are:
- Identify multiples of numbers
- Use common divisibility tests
- Find all the factors of a number.
- Identify prime and composite numbers
2.4.1 Identify Multiples of Numbers
Annie is counting the shoes in her closet. The shoes are matched in pairs, so she doesn’t have to count each one. She counts by twos: $2,4,6,8,10,12$. She has $12$ shoes in her closet.
The numbers $2,4,6,8,10,12$ are called multiples of $2$ Multiples of $2$ can be written as the product of a counting number and $2$. The first six multiples of $2$ are given below.
$1 \cdot 2 = 2$
$2 \cdot 2 = 4$
$3 \cdot 2 = 6$
$4 \cdot 2 = 8$
$5 \cdot 2 = 10$
$6 \cdot 2 = 12$
A multiple of a number is the product of the number and a counting number. So a multiple of $3$ would be the product of a counting number and $3$. Below are the first six multiples of $3$.
$1 \cdot 3 = 3$
$2 \cdot 3 = 6$
$3 \cdot 3 = 9$
$4 \cdot 3 = 12$
$5 \cdot 3 = 15$
$6 \cdot 3 = 18$
We can find the multiples of any number by continuing this process. The table below shows the multiples of 2 through 9 for the first twelve counting numbers.
Counting Number | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
---|---|---|---|---|---|---|---|---|---|---|---|---|
Multiples of 2 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 | 18 | 20 | 22 | 24 |
Multiples of 3 | 3 | 6 | 9 | 12 | 15 | 18 | 21 | 24 | 27 | 30 | 33 | 36 |
Multiples of 4 | 4 | 8 | 12 | 16 | 20 | 24 | 28 | 32 | 36 | 40 | 44 | 48 |
Multiples of 5 | 5 | 10 | 15 | 20 | 25 | 30 | 35 | 40 | 45 | 50 | 55 | 60 |
Multiples of 6 | 6 | 12 | 18 | 24 | 30 | 36 | 42 | 48 | 54 | 60 | 66 | 72 |
Multiples of 7 | 7 | 14 | 21 | 28 | 35 | 42 | 49 | 56 | 63 | 70 | 77 | 84 |
Multiples of 8 | 8 | 16 | 24 | 32 | 40 | 48 | 56 | 64 | 72 | 80 | 88 | 96 |
Multiples of 9 | 9 | 18 | 27 | 36 | 45 | 54 | 63 | 72 | 81 | 90 | 99 | 108 |
MULTIPLE OF A NUMBER
A number is a multiple of $n$ if it is the product of a counting number and $n$.
Recognizing the patterns for multiples of $2, 5, 10$, and $3$ will be helpful to you as you continue in this course.
MANIPULATIVE MATHEMATICS
Doing the Manipulative Mathematics activity “Multiples” will help you develop a better understanding of multiples.
The figure below shows the counting from $1$ to $50$. Multiples of $2$ are highlighted. Do you notice a pattern?
The last digit of each highlighted number in the figure above is either $0,2,4,6$, or $8$. This is true for the product of $2$ and any counting number. So, to tell if any number is a multiple of $2$ look at the last digit. If it is $0,2,4,6$, or $8$, then the number is a multiple of $2$.
Example 1
Determine whether each of the following is a multiple of $2$:
- $489$
- $3,714$
Solution
1. | |
Is $489$ a multiple of $2$? | |
Is the last digit $0, 2, 4, 6$, or $8$? | No. |
$489$ is not a multiple of $2$. | |
2. | |
Is $3,714$ a multiple of $2$? | |
Is the last digit $0,2,4,6$, or $8$? | Tes. |
$3,714$ is a multiple of $2$. |
Now let’s look at multiples of $5$. The figure below highlights all of the multiples of $5$ between $1$ and $50$. What do you notice about the multiples of $5$?
All multiples of $5$ end with either $5$ or $0$. Just like we identified multiples of $2$ by looking at the last digit, we can identify multiples of $5$ by looking at the last digit.
Example 2
Determine whether each of the following is a multiple of $5$:
- $579$
- $880$
Solution
1. | |
Is $579$ a multiple of $5$? | |
Is the last digit $5$ or $0$? | No. |
$579$ is not a multiple of $5$. | |
2. | |
Is $880$ a multiple of $5$? | |
Is the last digit $5$ or $0$? | Yes. |
$880$ is a multiple of $5$. |
The figure below highlights multiples of $10$ between $1$ and $50$. All multiples of $10$ all end with a zero.
Example 3
Determine whether each of the following is a multiple of $10$:
- $425$
- $350$
Solution
1. | |
Is $425$ a multiple of $10$? | |
Is the last digit zero? | No. |
$425$ is not a multiple of $10$. | |
2. | |
Is $350$ a multiple of $10$? | |
Is the last digit zero? | Yes. |
$350$ is a multiple of $10$. |
The figure below highlights multiples of $3$. The patter for multiples of $3$ is not as obvious as the patterns for multiples of $2,5$, and $10$.
Unlike the other patterns we’ve examined so far, this pattern does not involve the last digit. The pattern for multiples of $3$ is based on the sum of the digits. If the sum of the digits of a number is a multiple of $3$, then the number itself is a multiple of $3$. See the table below.
Multiple of 3 | $3$ | $6$ | $9$ | $12$ | $15$ | $18$ | $21$ | $24$ |
Sum of digits | $3$ | $6$ | $9$ | $1+2$ $3$ | $1+5$ $6$ | $1+8$ $9$ | $2+1$ $3$ | $2+4$ $6$ |
Consider the number $42$. The digits are $4$ and $2$, and their sum is $4+2=6$. Since $6$ is a multiple of $3$, we know that $42$ is also a multiple of $3$.
Example 4
Determine whether each of the given numbers is a multiple of $3$:
- $645$
- $10,519$
Solution
1. Is $645$ a multiple of $3$? | |
Find the sum of the digits. | $6+4+5=15$ |
Is $15$ a multiple of $3$? | Yes. |
If we’re not sure, we could add its digits to find out. We can check it by dividing $645$ by $3$. | $645 \div 3$ |
The quotient is $215$. | $3 \cdot 215 = 645$ |
2. Is $10,519$ a multiple of $3$? | |
Find the sum of the digits. | $1+0+5+1+9=16$ |
Is $16$ a multiple of $3$? | No. |
So $10,519$ is not a multiple of $3$ either. | $10,519 \div 3$ |
We can check this by dividing by $10,519$ by $3$. | $10,519 \div 3 = 3,506$ R$1$ |
When we divide $10,519$ by $3$, we do not get a counting number, so $10,519$ is not the product of a counting number and $3$. It is not a multiple of $3$.
Look back at the charts where you highlighted the multiples of $2$ of $5$, and of $10$. Notice that the multiples of $10$ are the numbers that are multiples of both $2$ and $5$. That is because $10=2 \cdot 5$. Likewise, since $6= 2 \cdot 3$, the multiples of $6$ are the numbers that are multiples of both $2$ and $3$.
2.4.2 Use Common Divisibility Tests
DIVISIBILITY
If a number $m$ is a multiple of $n$, then we say that $m$ is divisible by $n$.
Since multiplication and division are inverse operations, the patterns of multiples that we found can be used as divisibility tests. The table below summarizes divisibility tests for some of the counting numbers between one and ten.
Divisibility Tests
A number is divisible by | |
2 | if the last digit is $0,2,4,6$, or $8$ |
3 | if the sum of the digits is divisible by $3$ |
5 | if the last digit is $5$ or $0$ |
6 | if divisible by both $2$ and $3$ |
10 | if the last digit is $0$ |
Example 5
Determine whether $1,290$ is divisible by $2,3,5$, and $10$.
Solution
The table below applies the divisibility tests to $1,290$. In the far right column, we check the results of the divisibility tests by seeing if the quotient is a whole number.
Divisible by…? | Test | Divisible? | Check |
---|---|---|---|
2 | Is the last digit $0,2,4,5$, or $8$? Yes. | yes | $1290 \div 2 = 645$ |
3 | Is the sum of the digits divisible by $3$? $1+2+9+0=12$ Yes. | yes | $1290 \div 3 =430$ |
5 | Is the last digit $5$ or $0$? Yes. | yes | $1290 \div 5 = 258$ |
10 | Is the last digit $0$? Yes. | yes | $1290 \div 10 = 129$ |
Thus, $1,290$ is divisible by $2,3,5$, and $10$.
Example 6
Determine whether $5,625$ is divisible by $2,3,5$, and $10$.
Solution
The table below applies the divisibility tests to $5,625$ and tests the results by finding the quotients.
Divisible by…? | Test | Divisible? | Check |
---|---|---|---|
2 | Is the last digit $0,2,4,6$, or $8$? No. | no | $5625 \div 2 = 2812.5$ |
3 | Is the sum of digits divisible by $3$? $5+6+2+5=18$ Yes. | yes | $5625 \div 3 = 1875$ |
5 | Is the last digit a $5$ or $0$? Yes. | yes | $5625 \div 5 = 1125$ |
10 | Is the last digit a $0$? no | no | $5625 \div 10 = 562.5$ |
This, $5,625$ is divisible by $3$ and $5$, but not $2$, or $10$.
2.4.3 Find All the Factors of a Number
There are often several ways to talk about the same idea. So far, we’ve seen that if $m$ is a multiple of $n$, we can say that $m$ is divisible by $n$. We know that $72$ is the product of $8$ and $9$, so we can say $72$ is a multiple of $8$ and $72$ is a multiple of $9$. We can also say $72$ is divisible by $8$ and by $9$. Another way to talk about this is to say that $8$ and $9$ are factors of $72$. When we write $72=8 \cdot 9$ we can say that we have factored $72$.
Factors
In the expression $a \cdot b$, both $a$ and $b$ are called factors. If $a \cdot b =m$ and both $a$ and $b$ are integers, then $a$ and $b$ are factors of $m$, and $m$ is the product of $a$ and $b$.
In algebra, it can be useful to determine all of the factors of a number. This is called factoring a number, and it can help us solve many kinds of problems.
MANIPULATIVE MATHEMATICS
Doing the Manipulative Mathematics activity “Model Multiplication and Factoring” will help you develop a better understanding of multiplication and factoring.
For example, suppose a choreographer is planning a dance for a ballet recital. There are $24$ dancers, and for a certain scene, the choreographer wants to arrange the dancers in groups of equal sizes on stage.
In how many ways can the dancers be put into groups of equal size? Answering this question is the same as identifying the factors of $24$. The table below summarizes the different ways that the choreographer can arrange the dancers.
Number of Groups | Dancers per Group | Total Dancers |
---|---|---|
$1$ | $24$ | $1 \cdot 24 = 24$ |
$2$ | $12$ | $2 \cdot 12 = 24$ |
$3$ | $8$ | $3 \cdot 8 = 24$ |
$4$ | $6$ | $4 \cdot 6 = 24$ |
$6$ | $4$ | $6 \cdot 4 = 24$ |
$8$ | $3$ | $8 \cdot 3 = 24$ |
$12$ | $2$ | $12 \cdot 2= 24$ |
$24$ | $1$ | $24 \cdot 21 = 24$ |
What patterns do you see in the table above? Did you notice that the number of groups times the number of dancers per group is always $24$? This makes sense, since there are always $24$ dancers.
You may notice another pattern if you look carefully at the first two columns. These two columns contain the exact same set of numbers—but in reverse order. They are mirrors of one another, and in fact, both columns list all of the factors of $24$, which are:
$1,2,3,4,6,8,12,24$
We can find all the factors of any counting number by systematically dividing the number by each counting number, starting with $1$. If the quotient is also a counting number, then the divisor and the quotient are factors of the number. We can stop when the quotient becomes smaller than the divisor.
HOW TO: Find all the factors of a counting number.
- Divide the number by each of the counting numbers, in order, until the quotient is smaller than the divisor.
- If the quotient is a counting number, the divisor and quotient are a pair of factors.
- If the quotient is not a counting number, the divisor is not a factor.
- List all the factor pairs.
- Write all the factors in order from smallest to largest.
Example 7
Find all the factors of $72$.
Solution
Divide $72$ by each of the counting numbers starting with $1$. If the quotient is a whole number, the divisor and quotient are a pair of factors.
The next line would have a divisor of $9$ and a quotient of $8$. The quotient would be smaller than the divisor, so we stop. If we continued, we would end up only listing the same factors again in reverse order. Listing all the factors from smallest to greatest, we have
$1,2,3,4,6,8,9,12,18,24,36$, and $72$
2.4.4 Identify Prime and Composite Numbers
Some numbers, like $72$, have many factors. Other numbers, such as $7$, have only two factors: $1$ and the number. A number with only two factors is called a prime number. A number with more than two factors is called a composite number. The number $1$ is neither prime nor composite. It has only one factor, itself.
PRIME NUMBERS AND COMPOSITE NUMBERS
A prime number is a counting number greater than $1$ whose only factors are $1$ and itself.
A composite number is a counting number that is not prime.
The figure below lists the counting numbers from $2$ through $20$ along with their factors. The highlighted numbers are prime, since each has only two factors.
The prime numbers less than $20$ are $2,3,5,7,11,13,17$, and $19$. There are many larger prime numbers too. In order to determine whether a number is prime or composite, we need to see if the number has any factors other than $1$ and itself. To do this, we can test each of the smaller prime numbers in order to see if it is a factor of the number. If none of the prime numbers are factors, then that number is also prime.
HOW TO: Determine if a number is a prime.
- Test each of the primes, in order, to see if it is a factor of the number.
- Start with $2$ and stop when the quotient is smaller than the divisor or when a prime factor is found.
- If the number has a prime factor, then it is a composite number. If it has no prime factors, then the number is prime.
Example 8
Identify each number as prime or composite:
- 83
- 77
Solution
Part 1. Test each prime, in order, to see if it is a factor of $83$, starting with $2$, as shown. We will stop when the quotient is smaller than the divisor.
Prime | Test | Factor of $83$? |
---|---|---|
2 | Last digit of $83$ is not $0,2,4,6$, or $8$. | No. |
3 | $8+3=11$, and $11$ is not divisible by $3$. | No. |
5 | The last digit of $83$ is not $5$ or $0$. | No. |
7 | $83 \div 7 = 11.857…$ | No. |
11 | $83 \div 11 = 7.545…$ | No. |
We can stop when we get to $11$ because the quotient $(7.545…)$ is less than the divisor.
We did not find any prime numbers that are factors of $83$, so we know $83$ is prime.
Part 2. Test each prime, in order, to see if it is a factor of $77$.
Prime | Test | Factor of $77$? |
---|---|---|
2 | Last digit is not $0,2,4,6$, or $8$. | No. |
3 | $7+7=14$, and $14$ is not divisible by $3$. | No. |
5 | the last digit is not $5$ or $0$. | No. |
7 | $77 \div 7 = 11$ | Yes. |
Since $77$ is divisible by $7$, we know it is not a prime number. It is composite.
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- Revision and Adaptation. Provided by: Minute Math. License: CC BY 4.0
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- Marecek, L., Anthony-Smith, M., & Mathis, A. H. (2020). Use the Language of Algebra. In Prealgebra 2e. OpenStax. https://openstax.org/books/prealgebra-2e/pages/2-4-find-multiples-and-factors. License: CC BY 4.0. Access for free at https://openstax.org/books/prealgebra-2e/pages/1-introduction