**1.4 Multiply Whole Numbers**

The topics covered in this section are:

- Use multiplication notation
- Model multiplication of whole numbers
- Multiply whole numbers
- Translate word phrases to math notation
- Multiply whole numbers in applications

**1.4.1 Use Multiplication Notation**

Suppose you were asked to count all these pennies shown in the figure below.

Would you count the pennies individually? Or would you count the number of pennies in each row and add that number $3$ times.

$8+8+8$

Multiplication is a way to represent repeated addition. So instead of adding 88 three times, we could write a multiplication expression.

$3\times 8$

We call each number being multiplied a factor and the result the **product**. We read $3\times 8$ as *three times eight*, and the result as *the product of three and eight*.

**Operation Symbols for Multiplication**

To describe multiplication, we can use symbols and words.

Operation | Notation | Expression | Read as | Result |
---|---|---|---|---|

Multiplication | $\times$ $\cdot$ $( \ )$ | $3 \times 8$ $3 \cdot 8$ $3(8)$ | three times eight | the product of $3$ and $8$ |

**Example 1**

Translate from math notation to words:

- $7 \times 6$
- $12 \cdot 14$
- $6(13)$

**Solution**

- We read this as
*seven times six*and the result is*the product of seven and six*. - We read this as
*twelve times fourteen*and the result is*the product of twelve and fourteen*. - We read this as
*six times thirteen*and the result is*the product of six and thirteen*.

**1.4.2 Model Multiplication of Whole Numbers**

There are many ways to model multiplication. Unlike in the previous sections where we used base-$10$ blocks, here we will use counters to help us understand the meaning of multiplication. A counter is any object that can be used for counting. We will use round blue counters.

**Example 2**

Model: $3 \times 8$.

**Solution**

To model the product $3 \times 8$, we’ll start with a row of $8$ counters.

The other factor is $3$, so we’ll make $3$ rows of $8$ counters.

Now we can count the result. There are $24$ counters in all.

$3 \times 8 = 24$

If you look at the counters sideways, you’ll see that we could have also made $8$ rows of $3$ counters. The product would have been the same. We’ll get back to this idea later.

**1.4.3 Multiply Whole Numbers**

In order to multiply without using models, you need to know all the one digit multiplication facts. Make sure you know them fluently before proceeding in this section.

Table 1.4 shows the multiplication facts. Each box shows the product of the number down the left column and the number across the top row. If you are unsure about a product, model it. It is important that you memorize any number facts you do not already know so you will be ready to multiply larger numbers.

X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
---|---|---|---|---|---|---|---|---|---|---|

0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 | 0 |

1 | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |

2 | 0 | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 | 18 |

3 | 0 | 3 | 6 | 9 | 12 | 15 | 18 | 21 | 24 | 27 |

4 | 0 | 4 | 8 | 12 | 16 | 20 | 24 | 28 | 32 | 36 |

5 | 0 | 5 | 10 | 15 | 20 | 25 | 30 | 35 | 40 | 45 |

6 | 0 | 6 | 12 | 18 | 24 | 30 | 36 | 42 | 48 | 54 |

7 | 0 | 7 | 14 | 21 | 28 | 35 | 42 | 49 | 56 | 63 |

8 | 0 | 8 | 16 | 24 | 32 | 40 | 48 | 56 | 64 | 72 |

9 | 0 | 9 | 18 | 24 | 36 | 45 | 54 | 63 | 72 | 81 |

What happens when you multiply a number by zero? You can see that the product of any number and zero is zero. This is called the Multiplication Property of Zero.

**MULTIPLICATION PROPERTY OF ZERO**

The product of any number $0$ is $0$.

$a \cdot 0 = 0$

$0 \cdot a = 0$

**Example 3**

Multiply:

- $0 \cdot 11$
- $(42)0$

**Solution**

1. | $0 \cdot 11 $ |

The product of any number and zero is zero. | 0 |

2. | $(42)0$ |

Multiplying by zero results in zero. | 0 |

What happens when you multiply a number by one? Multiplying a number by one does not change its value. We call this fact the Identity Property of Multiplication, and $1$ is called the multiplicative identity.

**IDENTITY PROPERTY OF MULTIPLICATION**

The product of any number and $1$ is the number.

$1 \cdot a = a$

$a \cdot 1 = a$

**Example 4**

Multiply:

- $(11)1$
- $1 \cdot 42$

**Solution**

1. | $(11)1$ |

The product of any number and one is the number. | $11$ |

2. | $1 \cdot 42$ |

Multiplying by one does not change the value. | $42$ |

Earlier in this chapter, we learned that the Commutative Property of Addition states that changing the order of addition does not change the sum. We saw that $8+9=17$ is the same as $9+8=17$.

Is this also true for multiplication? Let’s look at a few pairs of factors.

$4 \cdot7=28$ | $7 \cdot 4 = 28$ |

$9 \cdot 7= 63$ | $7 \cdot 9 = 63$ |

$8 \cdot 9=72$ | $9 \cdot 8=72$ |

When the order of the factors is reversed, the product does not change. This is called the Commutative Property of Multiplication.

**COMMUTATIVE PROPERTY OF MULTIPLICATION**

Changing the order of the factors does not change their product.

$a \cdot b = b \cdot a$

**Example 5**

Multiply:

- $8 \cdot 7$
- $7 \cdot 8$

**Solution**

1. | $8 \cdot 7$ |

Multiply. | $56$ |

2. | $7 \cdot 8$ |

Multiply. | $56$ |

Changing the order of the factors does not change the product.

To multiply numbers with more than one digit, it is usually easier to write the numbers vertically in columns just as we did for addition and subtraction.

We start by multiplying $3$ by $7$.

We write the $1$ in the ones place of the product. We carry the $2$ tens by writing $2$ above the tens place.

Then we multiply the $3$ by the $2$, and add the $2$ above the tens place to the product. So $3 \times 2=6$, and $6+2=8$. Write the $8$ in the tens place of the product.

The product is $81$.

When we multiply two numbers with a different number of digits, it’s usually easier to write the smaller number on the bottom. You could write it the other way, too, but this way is easier to work with.

**Example 6**

Multiply: $15 \cdot 4 $.

**Solution**

Write the numbers so the digits $5$ and $4$ line up vertically. | |

Multiply $4$ by the digit in the ones place of $15$. $4 \cdot 5=20$ | |

Write $0$ in the ones place of the product and carry the $2$ tens. | |

Multiply $4$ by the digit in the tens place of $15$. $4 \cdot 1=4$. Add the $2$ tens we carried. $4+2=6$. | |

Write the $6$ in the tens place of the product. |

**Example 7**

Multiply: $286 \cdot 5$.

**Solution**

Write the numbers so the digits $5$ and $6$ line up vertically. | |

Multiply $5$ by the digit in the ones place of $286$. $5 \cdot 6=30$ | |

Write $0$ in the ones place of the product and carry the $3$ to the tens place. Multiply $5$ by the digit in the tens place of $286$. $5 \cdot 8=40$. | |

Add the $3$ tens we carried to get $40+3=43$. Write the $3$ in the tens place of the product and carry the $4$ to the hundreds place. | |

Multiply $5$ by the digit in the hundreds place of $286$. $5 \cdot 2=10$. Add the $4$ hundreds we carried to get $10+4=14$. Write the $4$ in the hundreds place of the product and the $1$ into the thousands place. |

When we multiply by a number with two or more digits, we multiply by each of the digits separately, working from right to left. Each separate product of the digits is called a partial product. When we write partial products, we must make sure to line up the place values.

**How to Multiply Two Whole Numbers to Find the Product.**

- Write the numbers so each place value lines up vertically.
- Multiply the digits in each place value.
- Work from right to left, starting with the ones place in the bottom number.
- Multiply the bottom number by the ones digit in the top number, then by the tens digit, and so on.
- If a product in a place value is more than $9$ carry to the next place value.
- Write the partial products, lining up the digits in the place values with the numbers above.

- Repeat for the tens place in the bottom number, the hundreds place, and so on.
- Insert a zero as a placeholder with each additional partial product.

- Work from right to left, starting with the ones place in the bottom number.
- Add the partial products.

**Example 8**

Multiply: $62(87)$.

**Solution**

Write the numbers so each place lines up vertically. | |

Start by multiplying $7$ by $62$. Multiply $7$ by the digit in the ones place of $62$. $7 \cdot 2=14$. Write the $4$ in the ones place of the product and carry the $1$ to the tens place. | |

Multiply $7$ by the digit in the tens place of $62$. $7 \cdot 2=42$. Add the $1$ ten we carried. $42+1=43$. Write the $3$ in the tens place of the product and the $4$ in the hundreds place. | |

The first partial product is $434$. | |

Now, write a $0$ under the $4$ in the ones place of the next partial product as a placeholder since we now multiply the digit in the tens place of $87$ by $62$. Multiply $8$ by the digit in the ones place of $62$. $8 \cdot 2=16$. Write the $6$ in the next place of the product, which is the tens place. Carry the $1$ to the tens place. | |

Multiply $8$ by $6$, the digit in the tens place of $62$, then add the $1$ ten we carried to get $49$. Write the $9$ in the hundreds place of the product and the $4$ in the thousands place. | |

The second partial product is $4960$. Add the partial products. |

The product is $5,394$.

**Example 9**

Multiply:

- $47 \cdot 10$.
- $47 \cdot 100$.

**Solution**

1. $47 \cdot 10$. | |

2. $47 \cdot 100$. |

When we multiplied $47$ times $10$, the product was $470$. Notice that $10$ has one zero, and we put one zero after $47$ to get the product. When we multiplied $47$ times $100$, the product was $4,700$. Notice that $100$ has two zeros and we put two zeros after $47$ to get the product.

Do you see the pattern? If we multiplied $47$ times $10,000$ which has four zeros, we would put four zeros after $47$ to get the product $470,000$.

**Example 10**

Multiply: $(354)(438)$.

**Solution**

There are three digits in the factors so there will be $3$ partial products. We do not have to write the $0$ as a placeholder as long as we write each partial product in the correct place.

**Example 11**

Multiply: $(896)201$.

**Solution**

There should be $3$ partial products. The second partial product will be the result of multiplying $896$ by $0$.

Notice that the second partial product of all zeros doesn’t really affect the result. We can place a zero as a placeholder in the tens place and then proceed directly to multiplying by the $2$ in the hundreds place, as shown.

Multiply by $10$ but insert only one zero as a placeholder in the tens place. Multiply by $200$, putting the $2$ from the $12$. $2 \cdot 6 = 12$ in the hundreds place.

When there are three or more factors, we multiply the first two and then multiply their product by the next factor. For example:

to multiply | $8 \cdot 3 \cdot 2$ |

first multiply $8 \cdot 3$ | $24 \cdot 2$ |

then multiply $24 \cdot 2$ | $48$ |

**1.4.4 Translate Word Phrases to Math Notation**

Earlier in this section, we translated math notation into words. Now we’ll reverse the process and translate word phrases into math notation. Some of the words that indicate multiplication are given in the table below.

Operation | Word Phrase | Example | Expression |
---|---|---|---|

Multiplication | times product twice | $3$ times $8$ the product of $3$ and $8$ twice $4$ | $3 \times 8$, $3 \cdot 8$, $(3)(8)$, $(3)8$, or $3(8)$ $2 \cdot 4$ |

**Example 12**

Translate and simplify: the product of $12$ and $27$.

**Solution**

The word *product* tells us to multiply. The words *of* $12$ *and* $27$ tell us the two factors.

the product of $12$ and $27$ | |

Translate. | $12 \cdot 27$ |

Multiply. | $324$ |

**Example 13**

Translate and simplify: twice two hundred eleven.

**Solution**

The word *twice* tells us to multiply by 2.

twice two hundred eleven | |

Translate. | $2(211)$ |

Multiply. | $422$ |

**1.4.5 Multiply Whole Numbers in Applications**

We will use the same strategy we used previously to solve applications of multiplication. First, we need to determine what we are looking for. Then we write a phrase that gives the information to find it. We then translate the phrase into math notation and simplify to get the answer. Finally, we write a sentence to answer the question.

**Example 14**

Humberto bought $4$ sheets of stamps. Each sheet had $20$ stamps. How many stamps did Humberto buy?

**Solution**

We are asked to find the total number of stamps.

Write a phrase for the total. | the product of $4$ and $20$ |

Translate to math notation. | $4 \cdot 20$ |

Multiply. | |

Write a sentence to answer the question. | Humberto bought $80$ stamps. |

**Example 15**

When Rena cooks rice, she uses twice as much water as rice. How much water does she need to cook $4$ cups of rice?

**Solution**

We are asked to find how much water Rena needs.

Write as a phrase. | twice as much as $4$ cups |

Translate to math notation. | $2 \cdot 4$ |

Multiply to simplify. | $8$ |

Write a sentence to answer the question. | Rena needs $8$ cups of water for $4$ cups of rice. |

**Example 16**

Van is planning to build a patio. He will have $8$ rows of tiles, with $14$ tiles in each row. How many tiles does he need for the patio?

**Solution**

We are asked to find the total number of tiles.

Write a phrase. | the product of $8$ and $14$ |

Translate to math notation. | $8 \cdot 14$ |

Multiply to simplify. | |

Write a sentence to answer the question. | Van needs $112$ tiles for his patio. |

If we want to know the size of a wall that needs to be painted or a floor that needs to be carpeted, we will need to find its **area**. The area is a measure of the amount of surface that is covered by the shape. Area is measured in square units. We often use square inches, square feet, square centimeters, or square miles to measure area. A square centimeter is a square that is one centimeter (cm.) on a side. A square inch is a square that is one inch on each side, and so on.

For a rectangular figure, the area is the product of the length and the width. Figure 1.12 shows a rectangular rug with a length of $2$ feet and a width of $3$ feet. Each square is $1$ foot wide by $1$ foot long, or $1$ square foot. The rug is made of $6$ squares. The area of the rug is $6$ square feet.

**Example 17**

Jen’s kitchen ceiling is a rectangle that measures $9$ feet long by $12$ feet wide. What is the area of Jen’s kitchen ceiling?

**Solution**

We are asked to find the area of the kitchen ceiling.

Write a phrase for the area. | the product of $9$ and $12$ |

Translate to math notation. | $9 \cdot 12$ |

Multiply. | |

Answer with a sentence. | The area of Jen’s kitchen ceiling is $108$ square feet. |

**Licenses and Attributions**

**Licenses and Attributions**

*CC Licensed Content, Original*

*Revision and Adaptation. Provided by: Minute Math. License: CC BY 4.0*

*CC Licensed Content, Shared Previously*

*Marecek, L., Anthony-Smith, M., & Mathis, A. H. (2020). Introduction to Whole Numbers. In Prealgebra 2e. OpenStax. https://openstax.org/books/prealgebra-2e/pages/1-4-multiply-whole-numbers. License: CC BY 4.0. Access for free at https://openstax.org/books/prealgebra-2e/pages/1-introduction*