6.4 General Strategy for Factoring Polynomials
Topics covered in this section are:
6.4.1 Recognize and Use the Appropriate Method to Factor a Polynomial Completely
GENERAL STRATEGY FOR FACTORING POLYNOMIALS

HOW TO: Use a general strategy for factoring polynomials.
- Is there a greatest common factor?
Factor it out. - Is the polynomial a binomial, trinomial, or are there more than three terms?
If it is a binomial:- Is it a sum?
Of squares? Sums of squares do not factor.
Of cubes? Use the sum of cubes pattern. - Is it a difference?
Of squares? Factor as the product of conjugates.
Of cubes? Use the difference of cubes pattern.If it is a trinomial:
- Is it of the form $x^{2}+bx+c$? Undo FOIL.
- Is it of the form $ax^{2}+bx+c$?
If $a$ and $c$ are squares, check if it fits the trinomial square pattern.
Use the trial and error or “ac” method.
If it has more than three terms:
- Use the grouping method.
- Is it a sum?
- Check.
Is it factored completely?
Do the factors multiply back to the original polynomial?
Remember, a polynomial is completely factored if, other than monomials, its factors are prime!
Example 1
Factor completely: $7x^{3}-21x^{2}-70x$.
Solution
$7x^{3}-21x^{2}-70x$ | |
Is there a GCF? Yes, $7x$. | |
Factor out the GCF. | $7x(x^{2}-3x-10)$ |
In the parentheses, is it a binomial, trinomial, or are there more terms? | |
It is a trinomial with leading coefficient $1$. | |
“Undo” FOIL. | $7x(x \ \ \ \ \ )(x \ \ \ \ \ \ )$ |
$7x(x+2)(x-5)$ | |
Is the expressions completely factored? Yes, neither binomial can be factored. | |
Check your answer by multiplying. | $7x(x+2)(x-5)$ $7x(x^{2}-5x+2x-10)$ $7x(x^{2}-3x-10$ $7x^{3}-21x^{2}-70x \ \checkmark$ |
Be careful when you are asked to factor a binomial as there are several options!
Example 2
Factor completely: $24y^{2}-150$.
Solution
$24y^{2}-150$ | |
Is there a GCF? Yes, $6$. | |
Factor out the GCF. | $6(4y^{2}-25)$ |
In the parentheses, is it a binomial, trinomial, or are there more than three terms. Binomial. | |
Is it a sum? No. | |
Is it a difference? Of squares or cubes? Yes, difference of squares. | $6((2y)^{2}-(5)^{2})$ |
Write as a product of conjugates. | $6(2y-5)(2y+5)$ |
Is the expression factored completely? Yes, neither binomial can be factored. | |
Check: | $6(2y-5)(2y+5)$ $6(4y^{2}-10y+10y-25)$ $24y^{2}-150 \ \checkmark$ |
The next example can be factored using several methods. recognizing the trinomial squares pattern will make your work easier.
Example 3
Factor completely: $4a^{2}-12ab+9b^{2}$.
Solution
$4a^{2}-12ab+9b^{2}$ | |
Is there a GCF? No. | |
Is it a binomial, trinomial, or are there more terms? | |
Trinomial with $a≠1$. But the first term is a perfect square. | |
Is the last term a perfect square? Yes. | $(2a)^{2}-12ab+(3b)^{2}$ |
Does it fit the pattern, $a^{2}-2ab+b^{2}$? Yes. | $(2a)^{2} \searrow – 12ab + \swarrow (3b)^{2}$ $-2(2a)(3b)$ |
Write it as a square. | $(2a-3b)^{2}$ |
Is the expression factored completely? Yes, the binomial cannot be factored. | |
Check your answer by multiplying. | $(2a-3b)^{2}$ $(2a)^{2}-2 \cdot 2a \cdot 3b + (3b)^{2}$ $4a^{2}-12ab+9b^{2} \ \checkmark$ |
Remember, sums of squares do not factor, but sums of cubes do!
Example 4
Factor completely: $12x^{3}y^{2}+75xy^{2}$.
Solution
$12x^{3}y^{2}+75xy^{2}$ | |
Is there a GCF? Yes, $3xy^{2}$. | |
Factor out the GCF. | $3xy^{2}(4x^{2}+25)$ |
In the parentheses, is it a binomial, trinomial, or are there more than three terms? It is a binomial. | |
Is it a sum? Of squares? Yes. | Sums of squares are prime. |
Is the expression factored completely? Yes. | |
Check: | $3xy^{2}(4x^{2}+25)$ $12x^{3}y^{2}+75xy^{2} \ \checkmark$ |
When using the sum or difference of cubes pattern, be careful with the signs.
Example 5
Factor completely: $24x^{3}+81y^{3}$.
Solution
$24x^{3}+81y^{3}$ | |
Is there a GCF? Yes, $3$. Factor it out. | $3(8x^{3}+27y^{3})$ |
In the parentheses, is it a binomial, trinomial, or are there more than three terms? Binomial. | |
Is it a sum or difference? Sum. | |
Sum of squares or cubes? Cubes. | ![]() |
Write it using the sum of cubes pattern. | ![]() |
Is the expression factored completely? Yes. | $3(2x+3y)(4x^{2}-6xy+9y^{2})$ |
Check by multiplying. | We leave this to you. |
Example 6
Factor completely: $3x^{5}y-48xy$.
Solution
$3x^{5}y-48xy$ | |
Is there a GCF? Yes, $3xy$. Factor it out. | $3xy(x^{4}-16)$ |
Is the binomial a sum or difference? Of squares or cubes? Write it as a difference of squares. | $3xy \left( (x^{2})^{2}-(4)^{2} \right)$ |
Factor it as a product of conjugates. | $3xy(x^{2}-4)(x^{2}+4)$ |
The first binomial is again a difference of squares. | $3xy \left( (x)^{2}-(2)^{2} \right) (x^{2}+4)$ |
Factor it as a product of conjugates. | $3xy(x-2)(x+2)(x^{2}+4)$ |
Is the expression factored completely? Yes. | |
Check by multiplying. | $3xy(x-2)(x+2)(x^{2}+4)$ $3xy(x^{2}-4)(x^{2}+4)$ $3xy(x^{4}-16)$ $3x^{5}y-48xy \ \checkmark$ |
Example 7
Factor completely: $4x^{2}+8bx-4ax-8ab$.
Solution
$4x^{2}+8bx-4ax-8ab$ | |
Is there a GCF? Factor out the GCF, $4$. | $4(x^{2}+2bx-ax-2ab)$ |
There are four terms, use grouping. | $4[x(x+2b)-a(x+ab)]$ $4(x+2b)(x-a)$ |
Is the expression completely factored? Yes. | |
Check your answer by multiplying. | $4(x+2b)(x-a)$ $4(x^{2}-ax+2bx-2ab)$ $4x^{2}+8bx-4ax-8ab \ \checkmark$ |
Taking out the complete GCF in the first step will always make your work easier.
Example 8
Factor completely: $40x^{2}+44xy-24y$.
Solution
$40x^{2}y+44xy-24y$ | |
Is there a GCF? Factor out the GCF, $4y$. | $4y(10x^{2}+11x-6)$ |
Factor the trinomial with $a≠1$. | $4y(5x-2)(2x+3)$ |
Is the expression completely factored? Yes. | |
Check your answer by multiplying. | $4y(5x-2)(2x+3)$ $4y(10x^{2}+11x-6)$ $40x^{2}y+44xy-24y \ \checkmark$ |
When we have factored a polynomial with four terms, most often we separated it into two groups of two terms. Remember that we can also separate it into a trinomial and then one term.
Example 9
Factor completely: $9x^{2}-12xy+4y^{2}-49$.
Solution
$9x^{2}-12xy+4y^{2}-49$ | |
Is there a GCF? No. | |
With more than $3$ terms, use grouping. Last $2$ terms have no GCF. Try grouping first $3$ terms. | |
Factor the trinomial with $a≠1$. But the first term is a perfect square. | $(3x)^{2}-12xy+(2y)^{2}-49$ |
Is the last term of the trinomial a perfect square? Yes. | |
Does the trinomial fit the pattern, $a^{2}-2ab+b^{2}$? Yes. | $(3x)^{2} _\searrow -12xy+ _\swarrow (2y)^{2}$ $-2(3x)(2y)$ |
Write the trinomial as a square. | $(3x-2y)^{2}-49$ |
Is this binomial a sum or difference? Of squares or cubes? Write it as a difference of squares. | $(3x-2y)^{2}-7^{2}$ |
Write it as a product of conjugates. | $((3x-2y)-7)((3x-2y)+7)$ $(3x-2y-7)(3x-2y+7)$ |
Is the expression factored completely? Yes. |
Check your answer by multiplying.
$(3x-2y-7)(3x-2y+7)$
$9x^{2}-6xy+21x-6xy+4y^{2}-14y-21x+14y-49$
$9x^{2}-12xy+4y^{2}-49 \ \checkmark$
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- Marecek, L., & Mathis, A. H. (2020). General Strategy for Factoring Polynomials. In Intermediate Algebra 2e. OpenStax. https://openstax.org/books/intermediate-algebra-2e/pages/6-4-general-strategy-for-factoring-polynomials. License: CC BY 4.0. Access for free at https://openstax.org/books/intermediate-algebra-2e/pages/1-introduction